an LFSR with length $L$ can be constructed with $2L$ sequential output regardless of the number of the taps. Use the Berlekamp-Massey algorithm, this is faster than Gaussian elimination and only requires the double of the LFSR's size.Give variable names for the internal and tap point then you can generate a linear equation of the system then solve it with Gaussian elimination.To find the taps and internal of an LFSR, you can go in two ways In this case, it visit all states except the all-zero state if it started with a non-zero sate. The LFSR is maximal-length if and only if the corresponding feedback polynomial is primitive. ![]() They have good statistical properties and one can calculate their period given the feedback polynomial. First of all, LFSR's are not secure when they are used alone.
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